Mn(II) and crystal field - normaly no temperature dependence of the product XT:
AI (Copilot) says: Key Points:
Electronic Configuration of Mn(II): Mn(II) has a 3d5 configuration.
In most cases, especially in octahedral or tetrahedral fields, Mn(II) remains high-spin due to the relatively weak crystal field splitting compared to the pairing energy.
Crystal Field Splitting: In a high-spin d5 system, all five d-orbitals are singly occupied.
This leads to maximum spin-only magnetic moment (5 unpaired electrons), which is approximately:
µeff = sqrt(n (n+2)) = (approx) 5.92 BM
Since there is no orbital contribution (due to half-filled shell symmetry and quenching), the susceptibility is largely spin-only.
Effect of Crystal Field:
For Mn(II), the crystal field effect is minimal on susceptibility because:
The d5 high-spin configuration is stable across most ligand fields.
Orbital angular momentum is quenched.
The ligand field does not significantly alter the number of unpaired electrons.